49z^2-56z+16=0

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Solution for 49z^2-56z+16=0 equation: 



49z^2-56z+16=0

a = 49; b = -56; c = +16;
Δ = b2-4ac
Δ = -562-4·49·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{56}{98}=4/7$

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